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Is it a bug in regex, or am I missing something?
I am a bit confused about what’s going on when I compile and run this program:
import java.util.regex.*;
class My {
public static void main(String[] args) throws Exception {
int myLines = 800000;
String myRegEx = “(/(?:(?<!\\\\)(?:[^\\/\\\\\x09\x0A\x0D\x20-])+?/)?/)(?=((?<!\\\\)(?:[^\\/\\\\\x09\x0A\x0D\x20-])+?/))";
String s = "A
\\\\\\\\
\\C
\\\\\\C
\\\\A
\\\\
A
\\\\
\\\\A";
System.out.println(myRegEx.matcher(s).find());
}
}
I would expect this to print 0. Instead, it returns 1. What am I missing? Thanks.
A:
Try using Java 8 Pattern matching which is default now.
What you are doing with your regex is splitting the string by any string that do not have a backslash or a linebreak. So this will match:
/A
or
\\\\/
The correct pattern will be:
/[^\\/]*(?:\\.[^\\/]*)*(?:\\.[^\\/]*)*(?:\\.[^\\/]*)*(?:[^\\/]*/)*[^\\/]*(?:[^\\/]*/)*[^\\/]*(?:\\.[^\\/]*)*[^\\/]*(?:[^\\/]*/)*(?:[^\\/
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